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3x^2-57x+26=0
a = 3; b = -57; c = +26;
Δ = b2-4ac
Δ = -572-4·3·26
Δ = 2937
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-57)-\sqrt{2937}}{2*3}=\frac{57-\sqrt{2937}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-57)+\sqrt{2937}}{2*3}=\frac{57+\sqrt{2937}}{6} $
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